armv6h vs. armv6l confusion

[lynix]

I'm a bit confused about these two mentioned architectural flavours.

On my freshly installed 'archlinux-hf-2013-02-11' image there is

$this->bbcode_second_pass_code('', 'CARCH="armv6h"')

in /etc/makepkg.conf and

$this->bbcode_second_pass_code('', 'Architecture = armv6h')

in /etc/pacman.conf, but the running kernel says

$this->bbcode_second_pass_code('', '$ uname -m
armv6l')


Can someone explain the difference between the two values, or why the "uname -m" output is different?

Thanks in advance,

lynix

[WarheadsSE]

the h stands for hard float. the l stands for little endian.

[lynix]

Okay, so why does 'uname -m' not report hard float as well? Is there no hard-float kernel available or are there no floating point operations in the kernel anyway?

[WarheadsSE]

The kernel is float agnostic, endian specific.

[kmihelich]

"armv6h" is purely arbitrary, I could make it say whatever I want it to, it doesn't matter.

"armv6l" is what GCC refers to the architecture as.

uname is not going to show what ABI the kernel is compiled with, I have no idea why it ever crossed your mind that it would.

If this doesn't make sense, go read something that explains it.